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5(2^3x+4)=1/6^x
We move all terms to the left:
5(2^3x+4)-(1/6^x)=0
Domain of the equation: 6^x)!=0We multiply parentheses
x!=0/1
x!=0
x∈R
10x^3-(1/6^x)+20=0
We get rid of parentheses
10x^3-1/6^x+20=0
We multiply all the terms by the denominator
10x^3*6^x+20*6^x-1=0
We do not support expression: x^3
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